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112025490784253 is a prime number
BaseRepresentation
bin11001011110001011110111…
…100101010111111111111101
3112200122112101001210122022122
4121132023313211113333331
5104140411201120044003
61034131444444452325
732411401044231104
oct3136136745277775
9480575331718278
10112025490784253
113277082005a522
121069335a24a0a5
134a67c5c948507
141d940c401103b
15ce409050a238
hex65e2f7957ffd

112025490784253 has 2 divisors, whose sum is σ = 112025490784254. Its totient is φ = 112025490784252.

The previous prime is 112025490784247. The next prime is 112025490784313. The reversal of 112025490784253 is 352487094520211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94128842808004 + 17896647976249 = 9702002^2 + 4230443^2 .

It is a cyclic number.

It is not a de Polignac number, because 112025490784253 - 234 = 112008310915069 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112025490784195 and 112025490784204.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112025490784243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56012745392126 + 56012745392127.

It is an arithmetic number, because the mean of its divisors is an integer number (56012745392127).

Almost surely, 2112025490784253 is an apocalyptic number.

It is an amenable number.

112025490784253 is a deficient number, since it is larger than the sum of its proper divisors (1).

112025490784253 is an equidigital number, since it uses as much as digits as its factorization.

112025490784253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4838400, while the sum is 53.

The spelling of 112025490784253 in words is "one hundred twelve trillion, twenty-five billion, four hundred ninety million, seven hundred eighty-four thousand, two hundred fifty-three".