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11203031113000 = 235323394789667
BaseRepresentation
bin1010001100000110100010…
…1100001001110100101000
31110122222222111111212011021
42203001220230021310220
52432022301431104000
635454333524542224
72234251361155426
oct243015054116450
943588874455137
1011203031113000
11362a1a7001181
12130b280551974
136335976cc1cc
142aa33003c116
1514663acbb11a
hexa3068b09d28

11203031113000 has 64 divisors (see below), whose sum is σ = 26226306100800. Its totient is φ = 4479295643200.

The previous prime is 11203031112983. The next prime is 11203031113019. The reversal of 11203031113000 is 31113030211.

It is a super-2 number, since 2×112030311130002 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 55834 + ... + 4733833.

It is an arithmetic number, because the mean of its divisors is an integer number (409786032825).

Almost surely, 211203031113000 is an apocalyptic number.

11203031113000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11203031113000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (13113153050400).

11203031113000 is an abundant number, since it is smaller than the sum of its proper divisors (15023274987800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11203031113000 is a wasteful number, since it uses less digits than its factorization.

11203031113000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4792027 (or 4792013 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 11203031113000 its reverse (31113030211), we get a palindrome (11234144143211).

The spelling of 11203031113000 in words is "eleven trillion, two hundred three billion, thirty-one million, one hundred thirteen thousand".

Divisors: 1 2 4 5 8 10 20 25 40 50 100 125 200 250 500 1000 2339 4678 9356 11695 18712 23390 46780 58475 93560 116950 233900 292375 467800 584750 1169500 2339000 4789667 9579334 19158668 23948335 38317336 47896670 95793340 119741675 191586680 239483350 478966700 598708375 957933400 1197416750 2394833500 4789667000 11203031113 22406062226 44812124452 56015155565 89624248904 112030311130 224060622260 280075777825 448121244520 560151555650 1120303111300 1400378889125 2240606222600 2800757778250 5601515556500 11203031113000