112031433124031 has 2 divisors, whose sum is σ = 112031433124032. Its totient is φ = 112031433124030.

The previous prime is 112031433123943. The next prime is 112031433124033. The reversal of 112031433124031 is 130421334130211.

It is a strong prime.

It is an emirp because it is prime and its reverse (130421334130211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-112031433124031 is a prime.

It is a super-3 number, since 3×112031433124031³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 112031433124033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 112031433123985 and 112031433124003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112031433124033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56015716562015 + 56015716562016.

It is an arithmetic number, because the mean of its divisors is an integer number (56015716562016).

Almost surely, 2^{112031433124031} is an apocalyptic number.

112031433124031 is a deficient number, since it is larger than the sum of its proper divisors (1).

112031433124031 is an equidigital number, since it uses as much as digits as its factorization.

112031433124031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 112031433124031 its reverse (130421334130211), we get a palindrome (242452767254242).

The spelling of 112031433124031 in words is "one hundred twelve trillion, thirty-one billion, four hundred thirty-three million, one hundred twenty-four thousand, thirty-one".