Base | Representation |
---|---|
bin | 10000010011011001101… |
… | …110110101101000001011 |
3 | 10222002210201200221122110 |
4 | 100103121232311220023 |
5 | 121323431133243430 |
6 | 2214402405153403 |
7 | 143641115352540 |
oct | 20233156655013 |
9 | 3862721627573 |
10 | 1120344431115 |
11 | 3a2154251228 |
12 | 1611690bb863 |
13 | 818569393b0 |
14 | 3c32140abc7 |
15 | 1e221aa57b0 |
hex | 104d9bb5a0b |
1120344431115 has 64 divisors (see below), whose sum is σ = 2335994228736. Its totient is φ = 444951263232.
The previous prime is 1120344431111. The next prime is 1120344431123. The reversal of 1120344431115 is 5111344430211.
It is a happy number.
It is not a de Polignac number, because 1120344431115 - 22 = 1120344431111 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1120344431111) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 24116947 + ... + 24163356.
It is an arithmetic number, because the mean of its divisors is an integer number (36499909824).
Almost surely, 21120344431115 is an apocalyptic number.
1120344431115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1120344431115 is an abundant number, since it is smaller than the sum of its proper divisors (1215649797621).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1120344431115 is a wasteful number, since it uses less digits than its factorization.
1120344431115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48280348.
The product of its (nonzero) digits is 5760, while the sum is 30.
Adding to 1120344431115 its reverse (5111344430211), we get a palindrome (6231688861326).
The spelling of 1120344431115 in words is "one trillion, one hundred twenty billion, three hundred forty-four million, four hundred thirty-one thousand, one hundred fifteen".
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