Base | Representation |
---|---|
bin | 110100001010111010… |
… | …1010101000011101101 |
3 | 101201011221110121101111 |
4 | 1220111311111003231 |
5 | 3313422033413432 |
6 | 123245100312021 |
7 | 11044225423162 |
oct | 1502565250355 |
9 | 351157417344 |
10 | 112035451117 |
11 | 43572100717 |
12 | 19868542611 |
13 | a746107455 |
14 | 55cb66a069 |
15 | 2daab5e347 |
hex | 1a15d550ed |
112035451117 has 2 divisors, whose sum is σ = 112035451118. Its totient is φ = 112035451116.
The previous prime is 112035451103. The next prime is 112035451123. The reversal of 112035451117 is 711154530211.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 71542340676 + 40493110441 = 267474^2 + 201229^2 .
It is a cyclic number.
It is not a de Polignac number, because 112035451117 - 215 = 112035418349 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112035421117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56017725558 + 56017725559.
It is an arithmetic number, because the mean of its divisors is an integer number (56017725559).
Almost surely, 2112035451117 is an apocalyptic number.
It is an amenable number.
112035451117 is a deficient number, since it is larger than the sum of its proper divisors (1).
112035451117 is an equidigital number, since it uses as much as digits as its factorization.
112035451117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4200, while the sum is 31.
Adding to 112035451117 its reverse (711154530211), we get a palindrome (823189981328).
The spelling of 112035451117 in words is "one hundred twelve billion, thirty-five million, four hundred fifty-one thousand, one hundred seventeen".
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