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1120413421300 = 225211204134213
BaseRepresentation
bin10000010011011101110…
…110000000111011110100
310222002222112112000101111
4100103131312000323310
5121324101313440200
62214413312004404
7143642613642235
oct20233566007364
93862875460344
101120413421300
113a218a192608
12161188230704
13818680133a4
143c32a64908c
151e227b820ba
hex104ddd80ef4

1120413421300 has 18 divisors (see below), whose sum is σ = 2431297124438. Its totient is φ = 448165368480.

The previous prime is 1120413421277. The next prime is 1120413421319. The reversal of 1120413421300 is 31243140211.

It can be written as a sum of positive squares in 3 ways, for example, as 200736257296 + 919677164004 = 448036^2 + 958998^2 .

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 5602067007 + ... + 5602067206.

Almost surely, 21120413421300 is an apocalyptic number.

1120413421300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1120413421300 is an abundant number, since it is smaller than the sum of its proper divisors (1310883703138).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1120413421300 is a wasteful number, since it uses less digits than its factorization.

1120413421300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11204134227 (or 11204134220 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 1120413421300 its reverse (31243140211), we get a palindrome (1151656561511).

The spelling of 1120413421300 in words is "one trillion, one hundred twenty billion, four hundred thirteen million, four hundred twenty-one thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 11204134213 22408268426 44816536852 56020671065 112041342130 224082684260 280103355325 560206710650 1120413421300