Base | Representation |
---|---|
bin | 10000010011011110111… |
… | …001100010111100000111 |
3 | 10222010000202211102020121 |
4 | 100103132321202330013 |
5 | 121324120331433411 |
6 | 2214415143242411 |
7 | 143643220263256 |
oct | 20233671427407 |
9 | 3863022742217 |
10 | 1120431124231 |
11 | 3a2199184031 |
12 | 161192149407 |
13 | 8186b8a10b3 |
14 | 3c32cb3679d |
15 | 1e2294cc571 |
hex | 104dee62f07 |
1120431124231 has 2 divisors, whose sum is σ = 1120431124232. Its totient is φ = 1120431124230.
The previous prime is 1120431124217. The next prime is 1120431124273. The reversal of 1120431124231 is 1324211340211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1120431124231 - 213 = 1120431116039 is a prime.
It is a super-2 number, since 2×11204311242312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1120431124196 and 1120431124205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1120431124201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560215562115 + 560215562116.
It is an arithmetic number, because the mean of its divisors is an integer number (560215562116).
Almost surely, 21120431124231 is an apocalyptic number.
1120431124231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120431124231 is an equidigital number, since it uses as much as digits as its factorization.
1120431124231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1120431124231 its reverse (1324211340211), we get a palindrome (2444642464442).
The spelling of 1120431124231 in words is "one trillion, one hundred twenty billion, four hundred thirty-one million, one hundred twenty-four thousand, two hundred thirty-one".
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