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11205314112647 is a prime number
BaseRepresentation
bin1010001100001111000011…
…0001000110110010000111
31110200012212121101020220202
42203003300301012302013
52432041440403101042
635455352241321115
72234362062303164
oct243036061066207
943605777336822
1011205314112647
113630168770646
12130b7b903619b
1363386c6a1385
142aa4a932306b
15146721430632
hexa30f0c46c87

11205314112647 has 2 divisors, whose sum is σ = 11205314112648. Its totient is φ = 11205314112646.

The previous prime is 11205314112617. The next prime is 11205314112659. The reversal of 11205314112647 is 74621141350211.

It is a strong prime.

It is an emirp because it is prime and its reverse (74621141350211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11205314112647 - 210 = 11205314111623 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11205314112647.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11205314112617) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5602657056323 + 5602657056324.

It is an arithmetic number, because the mean of its divisors is an integer number (5602657056324).

Almost surely, 211205314112647 is an apocalyptic number.

11205314112647 is a deficient number, since it is larger than the sum of its proper divisors (1).

11205314112647 is an equidigital number, since it uses as much as digits as its factorization.

11205314112647 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40320, while the sum is 38.

Adding to 11205314112647 its reverse (74621141350211), we get a palindrome (85826455462858).

The spelling of 11205314112647 in words is "eleven trillion, two hundred five billion, three hundred fourteen million, one hundred twelve thousand, six hundred forty-seven".