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1120998148031 is a prime number
BaseRepresentation
bin10000010100000000101…
…100100100011110111111
310222011111021210012200002
4100110000230210132333
5121331301011214111
62214551320424515
7143663244020006
oct20240054443677
93864437705602
101120998148031
113a245a259443
1216131001813b
138192c1c2138
143c384177c3d
151e25e18463b
hex10500b247bf

1120998148031 has 2 divisors, whose sum is σ = 1120998148032. Its totient is φ = 1120998148030.

The previous prime is 1120998147943. The next prime is 1120998148103. The reversal of 1120998148031 is 1308418990211.

Together with next prime (1120998148103) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (1308418990211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1120998148031 is a prime.

It is a super-2 number, since 2×11209981480312 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1120998148931) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560499074015 + 560499074016.

It is an arithmetic number, because the mean of its divisors is an integer number (560499074016).

Almost surely, 21120998148031 is an apocalyptic number.

1120998148031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1120998148031 is an equidigital number, since it uses as much as digits as its factorization.

1120998148031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 124416, while the sum is 47.

Subtracting from 1120998148031 its sum of digits (47), we obtain a square (1120998147984 = 10587722).

The spelling of 1120998148031 in words is "one trillion, one hundred twenty billion, nine hundred ninety-eight million, one hundred forty-eight thousand, thirty-one".