112100201120213 has 2 divisors, whose sum is σ = 112100201120214. Its totient is φ = 112100201120212.

The previous prime is 112100201120147. The next prime is 112100201120233. The reversal of 112100201120213 is 312021102001211.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101654648606449 + 10445552513764 = 10082393^2 + 3231958^2 .

It is an emirp because it is prime and its reverse (312021102001211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-112100201120213 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112100201120191 and 112100201120200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112100201120233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56050100560106 + 56050100560107.

It is an arithmetic number, because the mean of its divisors is an integer number (56050100560107).

Almost surely, 2^{112100201120213} is an apocalyptic number.

It is an amenable number.

112100201120213 is a deficient number, since it is larger than the sum of its proper divisors (1).

112100201120213 is an equidigital number, since it uses as much as digits as its factorization.

112100201120213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 112100201120213 its reverse (312021102001211), we get a palindrome (424121303121424).

The spelling of 112100201120213 in words is "one hundred twelve trillion, one hundred billion, two hundred one million, one hundred twenty thousand, two hundred thirteen".