Base | Representation |
---|---|
bin | 11001011111010011001000… |
… | …101111001100101010000011 |
3 | 112200220211220010012001002121 |
4 | 121133103020233030222003 |
5 | 104143134411121211121 |
6 | 1034230542052025111 |
7 | 32420050263001225 |
oct | 3137231057145203 |
9 | 480824803161077 |
10 | 112102014241411 |
11 | 327a02196004a7 |
12 | 106a6155902197 |
13 | 4a7223673788c |
14 | 1d97aa3176415 |
15 | ce606d6a2141 |
hex | 65f4c8bcca83 |
112102014241411 has 2 divisors, whose sum is σ = 112102014241412. Its totient is φ = 112102014241410.
The previous prime is 112102014241303. The next prime is 112102014241463. The reversal of 112102014241411 is 114142410201211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112102014241411 - 233 = 112093424306819 is a prime.
It is not a weakly prime, because it can be changed into another prime (112102014251411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56051007120705 + 56051007120706.
It is an arithmetic number, because the mean of its divisors is an integer number (56051007120706).
Almost surely, 2112102014241411 is an apocalyptic number.
112102014241411 is a deficient number, since it is larger than the sum of its proper divisors (1).
112102014241411 is an equidigital number, since it uses as much as digits as its factorization.
112102014241411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 512, while the sum is 25.
Adding to 112102014241411 its reverse (114142410201211), we get a palindrome (226244424442622).
The spelling of 112102014241411 in words is "one hundred twelve trillion, one hundred two billion, fourteen million, two hundred forty-one thousand, four hundred eleven".
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