Base | Representation |
---|---|
bin | 11001011111010011001000… |
… | …101111001100101000010111 |
3 | 112200220211220010012000221121 |
4 | 121133103020233030220113 |
5 | 104143134411121210203 |
6 | 1034230542052024411 |
7 | 32420050263001012 |
oct | 3137231057145027 |
9 | 480824803160847 |
10 | 112102014241303 |
11 | 327a0219600409 |
12 | 106a6155902107 |
13 | 4a72236737808 |
14 | 1d97aa3176379 |
15 | ce606d6a20bd |
hex | 65f4c8bcca17 |
112102014241303 has 2 divisors, whose sum is σ = 112102014241304. Its totient is φ = 112102014241302.
The previous prime is 112102014241289. The next prime is 112102014241411. The reversal of 112102014241303 is 303142410201211.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112102014241303 is a prime.
It is a super-2 number, since 2×1121020142413032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112102014841303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56051007120651 + 56051007120652.
It is an arithmetic number, because the mean of its divisors is an integer number (56051007120652).
Almost surely, 2112102014241303 is an apocalyptic number.
112102014241303 is a deficient number, since it is larger than the sum of its proper divisors (1).
112102014241303 is an equidigital number, since it uses as much as digits as its factorization.
112102014241303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 112102014241303 its reverse (303142410201211), we get a palindrome (415244424442514).
The spelling of 112102014241303 in words is "one hundred twelve trillion, one hundred two billion, fourteen million, two hundred forty-one thousand, three hundred three".
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