Base | Representation |
---|---|
bin | 1010001100100001010100… |
… | …1111110111001000110111 |
3 | 1110200200112120210011102201 |
4 | 2203020111033313020313 |
5 | 2432132013101401403 |
6 | 35501523211445331 |
7 | 2234624505221203 |
oct | 243102517671067 |
9 | 43620476704381 |
10 | 11210221122103 |
11 | 3632256634463 |
12 | 1310748456847 |
13 | 6341721a1a73 |
14 | 2aa812cd9b03 |
15 | 14690c11921d |
hex | a32153f7237 |
11210221122103 has 2 divisors, whose sum is σ = 11210221122104. Its totient is φ = 11210221122102.
The previous prime is 11210221122091. The next prime is 11210221122157. The reversal of 11210221122103 is 30122112201211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11210221122103 - 29 = 11210221121591 is a prime.
It is a super-3 number, since 3×112102211221033 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11210221122173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605110561051 + 5605110561052.
It is an arithmetic number, because the mean of its divisors is an integer number (5605110561052).
Almost surely, 211210221122103 is an apocalyptic number.
11210221122103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11210221122103 is an equidigital number, since it uses as much as digits as its factorization.
11210221122103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 11210221122103 its reverse (30122112201211), we get a palindrome (41332333323314).
The spelling of 11210221122103 in words is "eleven trillion, two hundred ten billion, two hundred twenty-one million, one hundred twenty-two thousand, one hundred three".
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