Base | Representation |
---|---|
bin | 10000010100000010001… |
… | …100100001101010100011 |
3 | 10222011120001010011211221 |
4 | 100110002030201222203 |
5 | 121331323431133212 |
6 | 2214554015515511 |
7 | 143664000564046 |
oct | 20240214415243 |
9 | 3864501104757 |
10 | 1121023302307 |
11 | 3a247247a1a7 |
12 | 161318528b97 |
13 | 8193448b61c |
14 | 3c387644c5d |
15 | 1e2614a2807 |
hex | 10502321aa3 |
1121023302307 has 2 divisors, whose sum is σ = 1121023302308. Its totient is φ = 1121023302306.
The previous prime is 1121023302263. The next prime is 1121023302323. The reversal of 1121023302307 is 7032033201211.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1121023302307 is a prime.
It is not a weakly prime, because it can be changed into another prime (1121023312307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560511651153 + 560511651154.
It is an arithmetic number, because the mean of its divisors is an integer number (560511651154).
Almost surely, 21121023302307 is an apocalyptic number.
1121023302307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121023302307 is an equidigital number, since it uses as much as digits as its factorization.
1121023302307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 1121023302307 its reverse (7032033201211), we get a palindrome (8153056503518).
The spelling of 1121023302307 in words is "one trillion, one hundred twenty-one billion, twenty-three million, three hundred two thousand, three hundred seven".
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