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11211000113 is a prime number
BaseRepresentation
bin10100111000011101…
…00100100100110001
31001221022110210222102
422130032210210301
5140430004000423
65052242350145
7544550633345
oct123416444461
931838423872
1011211000113
114833354355
12220a65b355
1310988637a1
14784d17625
1545936cc28
hex29c3a4931

11211000113 has 2 divisors, whose sum is σ = 11211000114. Its totient is φ = 11211000112.

The previous prime is 11211000091. The next prime is 11211000131. The reversal of 11211000113 is 31100011211.

It is a happy number.

Together with next prime (11211000131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9286598689 + 1924401424 = 96367^2 + 43868^2 .

It is an emirp because it is prime and its reverse (31100011211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11211000113 - 222 = 11206805809 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11211000094 and 11211000103.

It is not a weakly prime, because it can be changed into another prime (11211000133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605500056 + 5605500057.

It is an arithmetic number, because the mean of its divisors is an integer number (5605500057).

Almost surely, 211211000113 is an apocalyptic number.

It is an amenable number.

11211000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11211000113 is an equidigital number, since it uses as much as digits as its factorization.

11211000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 11211000113 its reverse (31100011211), we get a palindrome (42311011324).

The spelling of 11211000113 in words is "eleven billion, two hundred eleven million, one hundred thirteen", and thus it is an aban number.