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11211000131 is a prime number
BaseRepresentation
bin10100111000011101…
…00100100101000011
31001221022110211000002
422130032210211003
5140430004001011
65052242350215
7544550633402
oct123416444503
931838424002
1011211000131
114833354371
12220a65b36b
1310988637b6
14784d17639
1545936cc3b
hex29c3a4943

11211000131 has 2 divisors, whose sum is σ = 11211000132. Its totient is φ = 11211000130.

The previous prime is 11211000113. The next prime is 11211000133. The reversal of 11211000131 is 13100011211.

It is a happy number.

Together with previous prime (11211000113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11211000131 - 218 = 11210737987 is a prime.

It is a super-2 number, since 2×112110001312 (a number of 21 digits) contains 22 as substring.

Together with 11211000133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11211000133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605500065 + 5605500066.

It is an arithmetic number, because the mean of its divisors is an integer number (5605500066).

Almost surely, 211211000131 is an apocalyptic number.

11211000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11211000131 is an equidigital number, since it uses as much as digits as its factorization.

11211000131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 11211000131 its reverse (13100011211), we get a palindrome (24311011342).

The spelling of 11211000131 in words is "eleven billion, two hundred eleven million, one hundred thirty-one", and thus it is an aban number.