Base | Representation |
---|---|
bin | 10000010100000111011… |
… | …011001001011000111000 |
3 | 10222011210011011202102120 |
4 | 100110013123021120320 |
5 | 121332013410133422 |
6 | 2215010432001240 |
7 | 143666114306025 |
oct | 20240733113070 |
9 | 3864704152376 |
10 | 1121111021112 |
11 | 3a2507a42685 |
12 | 161341990220 |
13 | 819496c2144 |
14 | 3c39515a54c |
15 | 1e26902d45c |
hex | 105076c9638 |
1121111021112 has 128 divisors (see below), whose sum is σ = 2948780505600. Its totient is φ = 354704806400.
The previous prime is 1121111021087. The next prime is 1121111021137. The reversal of 1121111021112 is 2111201111211.
It is an interprime number because it is at equal distance from previous prime (1121111021087) and next prime (1121111021137).
It is a junction number, because it is equal to n+sod(n) for n = 1121111021091 and 1121111021100.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 17114662 + ... + 17180042.
It is an arithmetic number, because the mean of its divisors is an integer number (23037347700).
Almost surely, 21121111021112 is an apocalyptic number.
1121111021112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1121111021112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1474390252800).
1121111021112 is an abundant number, since it is smaller than the sum of its proper divisors (1827669484488).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1121111021112 is a wasteful number, since it uses less digits than its factorization.
1121111021112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65837 (or 65833 counting only the distinct ones).
The product of its (nonzero) digits is 8, while the sum is 15.
Adding to 1121111021112 its reverse (2111201111211), we get a palindrome (3232312132323).
Subtracting 1121111021112 from its reverse (2111201111211), we obtain a palindrome (990090090099).
The spelling of 1121111021112 in words is "one trillion, one hundred twenty-one billion, one hundred eleven million, twenty-one thousand, one hundred twelve".
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