Base | Representation |
---|---|
bin | 1010001100100100101001… |
… | …0010100011100111011111 |
3 | 1110200202211121021201020222 |
4 | 2203021022102203213133 |
5 | 2432140323410133043 |
6 | 35502151401231555 |
7 | 2234655532226534 |
oct | 243111222434737 |
9 | 43622747251228 |
10 | 11211111021023 |
11 | 3632672997711 |
12 | 13109564925bb |
13 | 63428466c884 |
14 | 2aa899186d8b |
15 | 1469602ecd68 |
hex | a324a4a39df |
11211111021023 has 2 divisors, whose sum is σ = 11211111021024. Its totient is φ = 11211111021022.
The previous prime is 11211111020987. The next prime is 11211111021049. The reversal of 11211111021023 is 32012011111211.
11211111021023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11211111021023 - 26 = 11211111020959 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11211111020992 and 11211111021010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11211111021073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605555510511 + 5605555510512.
It is an arithmetic number, because the mean of its divisors is an integer number (5605555510512).
Almost surely, 211211111021023 is an apocalyptic number.
11211111021023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11211111021023 is an equidigital number, since it uses as much as digits as its factorization.
11211111021023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 17.
Adding to 11211111021023 its reverse (32012011111211), we get a palindrome (43223122132234).
The spelling of 11211111021023 in words is "eleven trillion, two hundred eleven billion, one hundred eleven million, twenty-one thousand, twenty-three".
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