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1121112231433 is a prime number
BaseRepresentation
bin10000010100000111011…
…111110000111000001001
310222011210020110020200021
4100110013133300320021
5121332014212401213
62215010513540441
7143666130506455
oct20240737607011
93864706406607
101121112231433
113a2508699a47
12161342274721
1381949a26ccc
143c395393665
151e2691bbd8d
hex105077f0e09

1121112231433 has 2 divisors, whose sum is σ = 1121112231434. Its totient is φ = 1121112231432.

The previous prime is 1121112231431. The next prime is 1121112231469. The reversal of 1121112231433 is 3341322111211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 652610312649 + 468501918784 = 807843^2 + 684472^2 .

It is a cyclic number.

It is not a de Polignac number, because 1121112231433 - 21 = 1121112231431 is a prime.

Together with 1121112231431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1121112231398 and 1121112231407.

It is not a weakly prime, because it can be changed into another prime (1121112231431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560556115716 + 560556115717.

It is an arithmetic number, because the mean of its divisors is an integer number (560556115717).

Almost surely, 21121112231433 is an apocalyptic number.

It is an amenable number.

1121112231433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121112231433 is an equidigital number, since it uses as much as digits as its factorization.

1121112231433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 864, while the sum is 25.

Adding to 1121112231433 its reverse (3341322111211), we get a palindrome (4462434342644).

The spelling of 1121112231433 in words is "one trillion, one hundred twenty-one billion, one hundred twelve million, two hundred thirty-one thousand, four hundred thirty-three".