112112110212120 has 384 divisors, whose sum is σ = 393102977904000. Its totient is φ = 27637079703552.

The previous prime is 112112110212119. The next prime is 112112110212121. The reversal of 112112110212120 is 21212011211211.

It is a happy number.

112112110212120 is a `hidden beast` number, since 1 + 121 + 1 + 211 + 0 + 212 + 120 = 666.

It is an interprime number because it is at equal distance from previous prime (112112110212119) and next prime (112112110212121).

It is a super-3 number, since 3×112112110212120³ (a number of 43 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 112112110212093 and 112112110212102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (112112110212121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 44419624 + ... + 46875656.

It is an arithmetic number, because the mean of its divisors is an integer number (1023705671625).

Almost surely, 2^{112112110212120} is an apocalyptic number.

112112110212120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 112112110212120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (196551488952000).

112112110212120 is an abundant number, since it is smaller than the sum of its proper divisors (280990867691880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

112112110212120 is a wasteful number, since it uses less digits than its factorization.

112112110212120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2456259 (or 2456252 counting only the distinct ones).

The product of its (nonzero) digits is 32, while the sum is 18.

Adding to 112112110212120 its reverse (21212011211211), we get a palindrome (133324121423331).

Subtracting from 112112110212120 its reverse (21212011211211), we obtain a palindrome (90900099000909).

The spelling of 112112110212120 in words is "one hundred twelve trillion, one hundred twelve billion, one hundred ten million, two hundred twelve thousand, one hundred twenty".