Base | Representation |
---|---|
bin | 11001011111011100100011… |
… | …001001110011101101010111 |
3 | 112200221210222111000201012211 |
4 | 121133130203021303231113 |
5 | 104143321111000214033 |
6 | 1034235333013054251 |
7 | 32420555605615462 |
oct | 3137344311635527 |
9 | 480853874021184 |
10 | 112112121101143 |
11 | 327a4535671839 |
12 | 106a80b6627387 |
13 | 4a731875cac57 |
14 | 1d983815942d9 |
15 | ce6460b1c2cd |
hex | 65f723273b57 |
112112121101143 has 2 divisors, whose sum is σ = 112112121101144. Its totient is φ = 112112121101142.
The previous prime is 112112121101047. The next prime is 112112121101159. The reversal of 112112121101143 is 341101121211211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112112121101143 - 29 = 112112121100631 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112112121101443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56056060550571 + 56056060550572.
It is an arithmetic number, because the mean of its divisors is an integer number (56056060550572).
Almost surely, 2112112121101143 is an apocalyptic number.
112112121101143 is a deficient number, since it is larger than the sum of its proper divisors (1).
112112121101143 is an equidigital number, since it uses as much as digits as its factorization.
112112121101143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 22.
Adding to 112112121101143 its reverse (341101121211211), we get a palindrome (453213242312354).
The spelling of 112112121101143 in words is "one hundred twelve trillion, one hundred twelve billion, one hundred twenty-one million, one hundred one thousand, one hundred forty-three".
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