Base | Representation |
---|---|
bin | 1010001100100101111000… |
… | …1010010011111100110111 |
3 | 1110200210200211121022202111 |
4 | 2203021132022103330313 |
5 | 2432142014231412043 |
6 | 35502244430551451 |
7 | 2235000021024613 |
oct | 243113612237467 |
9 | 43623624538674 |
10 | 11211444404023 |
11 | 36328240a2256 |
12 | 1310a2a068587 |
13 | 634308758416 |
14 | 2aa8cb56a343 |
15 | 14697e70309d |
hex | a325e293f37 |
11211444404023 has 2 divisors, whose sum is σ = 11211444404024. Its totient is φ = 11211444404022.
The previous prime is 11211444404021. The next prime is 11211444404143. The reversal of 11211444404023 is 32040444411211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11211444404023 - 21 = 11211444404021 is a prime.
Together with 11211444404021, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11211444404021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5605722202011 + 5605722202012.
It is an arithmetic number, because the mean of its divisors is an integer number (5605722202012).
Almost surely, 211211444404023 is an apocalyptic number.
11211444404023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11211444404023 is an equidigital number, since it uses as much as digits as its factorization.
11211444404023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12288, while the sum is 31.
Adding to 11211444404023 its reverse (32040444411211), we get a palindrome (43251888815234).
The spelling of 11211444404023 in words is "eleven trillion, two hundred eleven billion, four hundred forty-four million, four hundred four thousand, twenty-three".
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