Base | Representation |
---|---|
bin | 11001011111100011111010… |
… | …000001111010111001100111 |
3 | 112200222120101001021100022221 |
4 | 121133203322001322321213 |
5 | 104143433300400232213 |
6 | 1034243120541333211 |
7 | 32421255433536463 |
oct | 3137437201727147 |
9 | 480876331240287 |
10 | 112120021102183 |
11 | 327a7919a49516 |
12 | 106a9740267207 |
13 | 4a73b461cab93 |
14 | 1d988d086b4a3 |
15 | ce677446338d |
hex | 65f8fa07ae67 |
112120021102183 has 2 divisors, whose sum is σ = 112120021102184. Its totient is φ = 112120021102182.
The previous prime is 112120021102157. The next prime is 112120021102241. The reversal of 112120021102183 is 381201120021211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112120021102183 - 245 = 76935649013351 is a prime.
It is a super-2 number, since 2×1121200211021832 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112120021102483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56060010551091 + 56060010551092.
It is an arithmetic number, because the mean of its divisors is an integer number (56060010551092).
Almost surely, 2112120021102183 is an apocalyptic number.
112120021102183 is a deficient number, since it is larger than the sum of its proper divisors (1).
112120021102183 is an equidigital number, since it uses as much as digits as its factorization.
112120021102183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 25.
Adding to 112120021102183 its reverse (381201120021211), we get a palindrome (493321141123394).
The spelling of 112120021102183 in words is "one hundred twelve trillion, one hundred twenty billion, twenty-one million, one hundred two thousand, one hundred eighty-three".
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