Base | Representation |
---|---|
bin | 1010001100101000000100… |
… | …0101011101000110010010 |
3 | 1110200212012200010121122221 |
4 | 2203022001011131012102 |
5 | 2432144214231131310 |
6 | 35502422521251254 |
7 | 2235020364241411 |
oct | 243120105350622 |
9 | 43625180117587 |
10 | 11212030333330 |
11 | 3632aa490a652 |
12 | 1310b72333b2a |
13 | 63439cc68658 |
14 | 2aa9452cd478 |
15 | 1469b5d91ada |
hex | a328115d192 |
11212030333330 has 32 divisors (see below), whose sum is σ = 21081215965824. Its totient is φ = 4285318832256.
The previous prime is 11212030333291. The next prime is 11212030333337. The reversal of 11212030333330 is 3333303021211.
It is a junction number, because it is equal to n+sod(n) for n = 11212030333295 and 11212030333304.
It is not an unprimeable number, because it can be changed into a prime (11212030333337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25356864 + ... + 25795243.
It is an arithmetic number, because the mean of its divisors is an integer number (658787998932).
Almost surely, 211212030333330 is an apocalyptic number.
11212030333330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11212030333330 is a deficient number, since it is larger than the sum of its proper divisors (9869185632494).
11212030333330 is a wasteful number, since it uses less digits than its factorization.
11212030333330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51153090.
The product of its (nonzero) digits is 2916, while the sum is 25.
Adding to 11212030333330 its reverse (3333303021211), we get a palindrome (14545333354541).
The spelling of 11212030333330 in words is "eleven trillion, two hundred twelve billion, thirty million, three hundred thirty-three thousand, three hundred thirty".
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