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1121210000023 is a prime number
BaseRepresentation
bin10000010100001101010…
…100101110001010010111
310222012001001102101222011
4100110031110232022113
5121332214230000043
62215024325245051
7144001425516211
oct20241524561227
93865031371864
101121210000023
113a25588a6a33
1216136ab63787
1381964068c49
143c3a43635b1
151e272a8059d
hex1050d52e297

1121210000023 has 2 divisors, whose sum is σ = 1121210000024. Its totient is φ = 1121210000022.

The previous prime is 1121210000003. The next prime is 1121210000051. The reversal of 1121210000023 is 3200000121211.

It is a weak prime.

It is an emirp because it is prime and its reverse (3200000121211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1121210000023 is a prime.

It is a super-2 number, since 2×11212100000232 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1121209999958 and 1121210000012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1121210000003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560605000011 + 560605000012.

It is an arithmetic number, because the mean of its divisors is an integer number (560605000012).

Almost surely, 21121210000023 is an apocalyptic number.

1121210000023 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121210000023 is an equidigital number, since it uses as much as digits as its factorization.

1121210000023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 1121210000023 its reverse (3200000121211), we get a palindrome (4321210121234).

The spelling of 1121210000023 in words is "one trillion, one hundred twenty-one billion, two hundred ten million, twenty-three", and thus it is an aban number.