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1121210019967 is a prime number
BaseRepresentation
bin10000010100001101010…
…100110011000001111111
310222012001001110102022211
4100110031110303001333
5121332214231114332
62215024325521251
7144001425631312
oct20241524630177
93865031412284
101121210019967
113a255890aa14
1216136ab73227
138196407504b
143c3a436a979
151e272a86447
hex1050d53307f

1121210019967 has 2 divisors, whose sum is σ = 1121210019968. Its totient is φ = 1121210019966.

The previous prime is 1121210019959. The next prime is 1121210019983. The reversal of 1121210019967 is 7699100121211.

It is a weak prime.

It is an emirp because it is prime and its reverse (7699100121211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1121210019967 - 23 = 1121210019959 is a prime.

It is a super-2 number, since 2×11212100199672 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1121210919967) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560605009983 + 560605009984.

It is an arithmetic number, because the mean of its divisors is an integer number (560605009984).

Almost surely, 21121210019967 is an apocalyptic number.

1121210019967 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121210019967 is an equidigital number, since it uses as much as digits as its factorization.

1121210019967 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13608, while the sum is 40.

The spelling of 1121210019967 in words is "one trillion, one hundred twenty-one billion, two hundred ten million, nineteen thousand, nine hundred sixty-seven".