Base | Representation |
---|---|
bin | 10000010100001101010… |
… | …100110011000010001111 |
3 | 10222012001001110102100102 |
4 | 100110031110303002033 |
5 | 121332214231114413 |
6 | 2215024325521315 |
7 | 144001425631334 |
oct | 20241524630217 |
9 | 3865031412312 |
10 | 1121210019983 |
11 | 3a255890aa29 |
12 | 16136ab7323b |
13 | 81964075061 |
14 | 3c3a436a98b |
15 | 1e272a86458 |
hex | 1050d53308f |
1121210019983 has 2 divisors, whose sum is σ = 1121210019984. Its totient is φ = 1121210019982.
The previous prime is 1121210019967. The next prime is 1121210020079. The reversal of 1121210019983 is 3899100121211.
It is a weak prime.
It is an emirp because it is prime and its reverse (3899100121211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1121210019983 - 24 = 1121210019967 is a prime.
It is a super-2 number, since 2×11212100199832 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1121210019883) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560605009991 + 560605009992.
It is an arithmetic number, because the mean of its divisors is an integer number (560605009992).
Almost surely, 21121210019983 is an apocalyptic number.
1121210019983 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121210019983 is an equidigital number, since it uses as much as digits as its factorization.
1121210019983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 38.
The spelling of 1121210019983 in words is "one trillion, one hundred twenty-one billion, two hundred ten million, nineteen thousand, nine hundred eighty-three".
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