Base | Representation |
---|---|
bin | 110100001101011101… |
… | …1101101010110111111 |
3 | 101201101220110102120011 |
4 | 1220122323231112333 |
5 | 3314110434301344 |
6 | 123301354204051 |
7 | 11046314566624 |
oct | 1503273552677 |
9 | 351356412504 |
10 | 112121009599 |
11 | 43606429005 |
12 | 19891123627 |
13 | a75aa62881 |
14 | 55d8b7c34b |
15 | 2db340ed34 |
hex | 1a1aeed5bf |
112121009599 has 2 divisors, whose sum is σ = 112121009600. Its totient is φ = 112121009598.
The previous prime is 112121009549. The next prime is 112121009603. The reversal of 112121009599 is 995900121211.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (995900121211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 112121009599 - 231 = 109973525951 is a prime.
It is a super-2 number, since 2×1121210095992 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112121009519) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56060504799 + 56060504800.
It is an arithmetic number, because the mean of its divisors is an integer number (56060504800).
Almost surely, 2112121009599 is an apocalyptic number.
112121009599 is a deficient number, since it is larger than the sum of its proper divisors (1).
112121009599 is an equidigital number, since it uses as much as digits as its factorization.
112121009599 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14580, while the sum is 40.
The spelling of 112121009599 in words is "one hundred twelve billion, one hundred twenty-one million, nine thousand, five hundred ninety-nine".
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