Base | Representation |
---|---|
bin | 10000010100001101011… |
… | …001010101100111000101 |
3 | 10222012001010200212222211 |
4 | 100110031121111213011 |
5 | 121332220032211211 |
6 | 2215024411223421 |
7 | 144001442016316 |
oct | 20241531254705 |
9 | 3865033625884 |
10 | 1121211210181 |
11 | 3a2559553167 |
12 | 16136b447b71 |
13 | 819643a0a0a |
14 | 3c3a459a60d |
15 | 1e272c1de21 |
hex | 1050d6559c5 |
1121211210181 has 2 divisors, whose sum is σ = 1121211210182. Its totient is φ = 1121211210180.
The previous prime is 1121211210139. The next prime is 1121211210221. The reversal of 1121211210181 is 1810121121211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1068525353025 + 52685857156 = 1033695^2 + 229534^2 .
It is a cyclic number.
It is not a de Polignac number, because 1121211210181 - 211 = 1121211208133 is a prime.
It is a super-2 number, since 2×11212112101812 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1121211210131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560605605090 + 560605605091.
It is an arithmetic number, because the mean of its divisors is an integer number (560605605091).
Almost surely, 21121211210181 is an apocalyptic number.
It is an amenable number.
1121211210181 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121211210181 is an equidigital number, since it uses as much as digits as its factorization.
1121211210181 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 22.
Adding to 1121211210181 its reverse (1810121121211), we get a palindrome (2931332331392).
The spelling of 1121211210181 in words is "one trillion, one hundred twenty-one billion, two hundred eleven million, two hundred ten thousand, one hundred eighty-one".
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