Base | Representation |
---|---|
bin | 10000010100001101011… |
… | …010001011100110000100 |
3 | 10222012001011010010022102 |
4 | 100110031122023212010 |
5 | 121332220111300200 |
6 | 2215024420051232 |
7 | 144001443630062 |
oct | 20241532134604 |
9 | 3865034103272 |
10 | 1121211431300 |
11 | 3a2559694304 |
12 | 16136b533b18 |
13 | 8196444a55c |
14 | 3c3a4617032 |
15 | 1e272c646d5 |
hex | 1050d68b984 |
1121211431300 has 72 divisors (see below), whose sum is σ = 2574570966912. Its totient is φ = 422943136000.
The previous prime is 1121211431299. The next prime is 1121211431311. The reversal of 1121211431300 is 31341121211.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3269681 + ... + 3596280.
It is an arithmetic number, because the mean of its divisors is an integer number (35757930096).
Almost surely, 21121211431300 is an apocalyptic number.
1121211431300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1121211431300 is an abundant number, since it is smaller than the sum of its proper divisors (1453359535612).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1121211431300 is a wasteful number, since it uses less digits than its factorization.
1121211431300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6866069 (or 6866062 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 1121211431300 its reverse (31341121211), we get a palindrome (1152552552511).
The spelling of 1121211431300 in words is "one trillion, one hundred twenty-one billion, two hundred eleven million, four hundred thirty-one thousand, three hundred".
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