Base | Representation |
---|---|
bin | 1010001100101000011001… |
… | …1111010100100011001101 |
3 | 1110200212102222201222010222 |
4 | 2203022012133110203031 |
5 | 2432144410434001031 |
6 | 35502435520441125 |
7 | 2235022545012215 |
oct | 243120637244315 |
9 | 43625388658128 |
10 | 11212121000141 |
11 | 36330410069a6 |
12 | 1310b987791a5 |
13 | 6343b5991c59 |
14 | 2aa953371245 |
15 | 1469bdd00e7b |
hex | a32867d48cd |
11212121000141 has 2 divisors, whose sum is σ = 11212121000142. Its totient is φ = 11212121000140.
The previous prime is 11212121000107. The next prime is 11212121000159. The reversal of 11212121000141 is 14100012121211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11195354634916 + 16766365225 = 3345946^2 + 129485^2 .
It is a cyclic number.
It is not a de Polignac number, because 11212121000141 - 214 = 11212120983757 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11212121000161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606060500070 + 5606060500071.
It is an arithmetic number, because the mean of its divisors is an integer number (5606060500071).
Almost surely, 211212121000141 is an apocalyptic number.
It is an amenable number.
11212121000141 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212121000141 is an equidigital number, since it uses as much as digits as its factorization.
11212121000141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32, while the sum is 17.
Adding to 11212121000141 its reverse (14100012121211), we get a palindrome (25312133121352).
The spelling of 11212121000141 in words is "eleven trillion, two hundred twelve billion, one hundred twenty-one million, one hundred forty-one", and thus it is an aban number.
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