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11212121000142 = 233207631870373
BaseRepresentation
bin1010001100101000011001…
…1111010100100011001110
31110200212102222201222011000
42203022012133110203032
52432144410434001032
635502435520441130
72235022545012216
oct243120637244316
943625388658130
1011212121000142
1136330410069a7
121310b987791a6
136343b5991c5a
142aa953371246
151469bdd00e7c
hexa32867d48ce

11212121000142 has 16 divisors (see below), whose sum is σ = 24915824444880. Its totient is φ = 3737373666696.

The previous prime is 11212121000141. The next prime is 11212121000159. The reversal of 11212121000142 is 24100012121211.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11212121000141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 103815935133 + ... + 103815935240.

It is an arithmetic number, because the mean of its divisors is an integer number (1557239027805).

Almost surely, 211212121000142 is an apocalyptic number.

11212121000142 is an abundant number, since it is smaller than the sum of its proper divisors (13703703444738).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11212121000142 is a wasteful number, since it uses less digits than its factorization.

11212121000142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 207631870384 (or 207631870378 counting only the distinct ones).

The product of its (nonzero) digits is 64, while the sum is 18.

Adding to 11212121000142 its reverse (24100012121211), we get a palindrome (35312133121353).

The spelling of 11212121000142 in words is "eleven trillion, two hundred twelve billion, one hundred twenty-one million, one hundred forty-two", and thus it is an aban number.

Divisors: 1 2 3 6 9 18 27 54 207631870373 415263740746 622895611119 1245791222238 1868686833357 3737373666714 5606060500071 11212121000142