Base | Representation |
---|---|
bin | 1010001100101000011001… |
… | …1111010100100011100001 |
3 | 1110200212102222201222011201 |
4 | 2203022012133110203201 |
5 | 2432144410434001121 |
6 | 35502435520441201 |
7 | 2235022545012244 |
oct | 243120637244341 |
9 | 43625388658151 |
10 | 11212121000161 |
11 | 3633041006a14 |
12 | 1310b98779201 |
13 | 6343b5991c73 |
14 | 2aa95337125b |
15 | 1469bdd00e91 |
hex | a32867d48e1 |
11212121000161 has 2 divisors, whose sum is σ = 11212121000162. Its totient is φ = 11212121000160.
The previous prime is 11212121000159. The next prime is 11212121000183. The reversal of 11212121000161 is 16100012121211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7691919511761 + 3520201488400 = 2773431^2 + 1876220^2 .
It is a cyclic number.
It is not a de Polignac number, because 11212121000161 - 21 = 11212121000159 is a prime.
Together with 11212121000159, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11212121000141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606060500080 + 5606060500081.
It is an arithmetic number, because the mean of its divisors is an integer number (5606060500081).
Almost surely, 211212121000161 is an apocalyptic number.
It is an amenable number.
11212121000161 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212121000161 is an equidigital number, since it uses as much as digits as its factorization.
11212121000161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 11212121000161 its reverse (16100012121211), we get a palindrome (27312133121372).
The spelling of 11212121000161 in words is "eleven trillion, two hundred twelve billion, one hundred twenty-one million, one hundred sixty-one", and thus it is an aban number.
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