Base | Representation |
---|---|
bin | 10100111000100101… |
… | …10110010000011001 |
3 | 1001221101120202200221 |
4 | 22130102312100121 |
5 | 140430300333423 |
6 | 5052322400041 |
7 | 544563312514 |
oct | 123422662031 |
9 | 31841522627 |
10 | 11212121113 |
11 | 4833a4a5a6 |
12 | 220ab00021 |
13 | 1098b66abb |
14 | 785129d7b |
15 | 4594dee5d |
hex | 29c4b6419 |
11212121113 has 2 divisors, whose sum is σ = 11212121114. Its totient is φ = 11212121112.
The previous prime is 11212121101. The next prime is 11212121119. The reversal of 11212121113 is 31112121211.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8874205209 + 2337915904 = 94203^2 + 48352^2 .
It is a cyclic number.
It is not a de Polignac number, because 11212121113 - 221 = 11210023961 is a prime.
It is not a weakly prime, because it can be changed into another prime (11212121119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606060556 + 5606060557.
It is an arithmetic number, because the mean of its divisors is an integer number (5606060557).
Almost surely, 211212121113 is an apocalyptic number.
It is an amenable number.
11212121113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212121113 is an equidigital number, since it uses as much as digits as its factorization.
11212121113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 24, while the sum is 16.
Adding to 11212121113 its reverse (31112121211), we get a palindrome (42324242324).
The spelling of 11212121113 in words is "eleven billion, two hundred twelve million, one hundred twenty-one thousand, one hundred thirteen".
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