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112121213203 is a prime number
BaseRepresentation
bin110100001101011110…
…0011111000100010011
3101201101220211202212001
41220122330133010103
53314111012310303
6123301402414431
711046316405336
oct1503274370423
9351356752761
10112121213203
1143606557a7a
1219891201417
13a75ab0444c
1455d8bd261d
152db345031d
hex1a1af1f113

112121213203 has 2 divisors, whose sum is σ = 112121213204. Its totient is φ = 112121213202.

The previous prime is 112121213201. The next prime is 112121213221. The reversal of 112121213203 is 302312121211.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 112121213203 - 21 = 112121213201 is a prime.

It is a super-2 number, since 2×1121212132032 (a number of 23 digits) contains 22 as substring.

Together with 112121213201, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (112121213201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56060606601 + 56060606602.

It is an arithmetic number, because the mean of its divisors is an integer number (56060606602).

Almost surely, 2112121213203 is an apocalyptic number.

112121213203 is a deficient number, since it is larger than the sum of its proper divisors (1).

112121213203 is an equidigital number, since it uses as much as digits as its factorization.

112121213203 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 112121213203 its reverse (302312121211), we get a palindrome (414433334414).

The spelling of 112121213203 in words is "one hundred twelve billion, one hundred twenty-one million, two hundred thirteen thousand, two hundred three".