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112121213201 is a prime number
BaseRepresentation
bin110100001101011110…
…0011111000100010001
3101201101220211202211222
41220122330133010101
53314111012310301
6123301402414425
711046316405334
oct1503274370421
9351356752758
10112121213201
1143606557a78
1219891201415
13a75ab0444a
1455d8bd261b
152db345031b
hex1a1af1f111

112121213201 has 2 divisors, whose sum is σ = 112121213202. Its totient is φ = 112121213200.

The previous prime is 112121213189. The next prime is 112121213203. The reversal of 112121213201 is 102312121211.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 103137964801 + 8983248400 = 321151^2 + 94780^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112121213201 is a prime.

Together with 112121213203, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 112121213201.

It is not a weakly prime, because it can be changed into another prime (112121213203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56060606600 + 56060606601.

It is an arithmetic number, because the mean of its divisors is an integer number (56060606601).

Almost surely, 2112121213201 is an apocalyptic number.

It is an amenable number.

112121213201 is a deficient number, since it is larger than the sum of its proper divisors (1).

112121213201 is an equidigital number, since it uses as much as digits as its factorization.

112121213201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 112121213201 its reverse (102312121211), we get a palindrome (214433334412).

The spelling of 112121213201 in words is "one hundred twelve billion, one hundred twenty-one million, two hundred thirteen thousand, two hundred one".