1121212404133 has 2 divisors, whose sum is σ = 1121212404134. Its totient is φ = 1121212404132.

The previous prime is 1121212404061. The next prime is 1121212404157. The reversal of 1121212404133 is 3314042121211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1006133375844 + 115079028289 = 1003062^2 + 339233^2 .

It is a cyclic number.

It is not a de Polignac number, because 1121212404133 - 2²¹ = 1121210306981 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1121212404098 and 1121212404107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1121212404833) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560606202066 + 560606202067.

It is an arithmetic number, because the mean of its divisors is an integer number (560606202067).

Almost surely, 2^{1121212404133} is an apocalyptic number.

It is an amenable number.

1121212404133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121212404133 is an equidigital number, since it uses as much as digits as its factorization.

1121212404133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1121212404133 its reverse (3314042121211), we get a palindrome (4435254525344).

The spelling of 1121212404133 in words is "one trillion, one hundred twenty-one billion, two hundred twelve million, four hundred four thousand, one hundred thirty-three".