Base | Representation |
---|---|
bin | 10100111000100110… |
… | …01110101011001011 |
3 | 1001221101202211220022 |
4 | 22130103032223023 |
5 | 140430312034011 |
6 | 5052324451055 |
7 | 544564210226 |
oct | 123423165313 |
9 | 31841684808 |
10 | 11212221131 |
11 | 4834008761 |
12 | 220ab49a8b |
13 | 1098ba0497 |
14 | 7851545bd |
15 | 45950e8db |
hex | 29c4ceacb |
11212221131 has 2 divisors, whose sum is σ = 11212221132. Its totient is φ = 11212221130.
The previous prime is 11212221127. The next prime is 11212221133. The reversal of 11212221131 is 13112221211.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11212221131 - 22 = 11212221127 is a prime.
It is a super-2 number, since 2×112122211312 (a number of 21 digits) contains 22 as substring.
Together with 11212221133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (11212221133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606110565 + 5606110566.
It is an arithmetic number, because the mean of its divisors is an integer number (5606110566).
Almost surely, 211212221131 is an apocalyptic number.
11212221131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212221131 is an equidigital number, since it uses as much as digits as its factorization.
11212221131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 48, while the sum is 17.
Adding to 11212221131 its reverse (13112221211), we get a palindrome (24324442342).
The spelling of 11212221131 in words is "eleven billion, two hundred twelve million, two hundred twenty-one thousand, one hundred thirty-one".
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