Base | Representation |
---|---|
bin | 11001011111101110100001… |
… | …100010101001101100101100 |
3 | 112201000122210112222002121001 |
4 | 121133232201202221230230 |
5 | 104144130122340142030 |
6 | 1034252244105450044 |
7 | 32422141103554654 |
oct | 3137564142515454 |
9 | 481018715862531 |
10 | 112131421412140 |
11 | 3280173a144089 |
12 | 106ab9a21a0924 |
13 | 4a74c42044c10 |
14 | 1d99292983364 |
15 | ce6be0227cca |
hex | 65fba18a9b2c |
112131421412140 has 96 divisors (see below), whose sum is σ = 268545001584384. Its totient is φ = 38961357557760.
The previous prime is 112131421412117. The next prime is 112131421412149. The reversal of 112131421412140 is 41214124131211.
It is a junction number, because it is equal to n+sod(n) for n = 112131421412099 and 112131421412108.
It is not an unprimeable number, because it can be changed into a prime (112131421412149) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 29113885 + ... + 32739595.
It is an arithmetic number, because the mean of its divisors is an integer number (2797343766504).
Almost surely, 2112131421412140 is an apocalyptic number.
112131421412140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 112131421412140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (134272500792192).
112131421412140 is an abundant number, since it is smaller than the sum of its proper divisors (156413580172244).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112131421412140 is a wasteful number, since it uses less digits than its factorization.
112131421412140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3632747 (or 3632745 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 28.
Adding to 112131421412140 its reverse (41214124131211), we get a palindrome (153345545543351).
The spelling of 112131421412140 in words is "one hundred twelve trillion, one hundred thirty-one billion, four hundred twenty-one million, four hundred twelve thousand, one hundred forty".
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