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1121321001001 is a prime number
BaseRepresentation
bin10000010100010011111…
…100001010000000101001
310222012022210021211200111
4100110103330022000221
5121332431134013001
62215043332334321
7144004244150215
oct20242374120051
93865283254614
101121321001001
113a2605521683
121613a01743a1
1381981061ab6
143c3b4db9945
151e27c6a9851
hex10513f0a029

1121321001001 has 2 divisors, whose sum is σ = 1121321001002. Its totient is φ = 1121321001000.

The previous prime is 1121321000999. The next prime is 1121321001121. The reversal of 1121321001001 is 1001001231211.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 893743344400 + 227577656601 = 945380^2 + 477051^2 .

It is an emirp because it is prime and its reverse (1001001231211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1121321001001 - 21 = 1121321000999 is a prime.

Together with 1121321000999, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1121321001301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560660500500 + 560660500501.

It is an arithmetic number, because the mean of its divisors is an integer number (560660500501).

Almost surely, 21121321001001 is an apocalyptic number.

It is an amenable number.

1121321001001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121321001001 is an equidigital number, since it uses as much as digits as its factorization.

1121321001001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 1121321001001 its reverse (1001001231211), we get a palindrome (2122322232212).

The spelling of 1121321001001 in words is "one trillion, one hundred twenty-one billion, three hundred twenty-one million, one thousand, one".