Search a number
-
+
112132113491 is a prime number
BaseRepresentation
bin110100001101110011…
…0000100010001010011
3101201102200100120020102
41220123212010101103
53314121310112431
6123302432203015
711046511144526
oct1503346042123
9351380316212
10112132113491
1143611722582
121989499946b
13a76014ca18
1455da42cbbd
152db43a4dcb
hex1a1b984453

112132113491 has 2 divisors, whose sum is σ = 112132113492. Its totient is φ = 112132113490.

The previous prime is 112132113479. The next prime is 112132113493. The reversal of 112132113491 is 194311231211.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 112132113491 - 226 = 112065004627 is a prime.

It is a super-2 number, since 2×1121321134912 (a number of 23 digits) contains 22 as substring.

Together with 112132113493, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (112132113493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56066056745 + 56066056746.

It is an arithmetic number, because the mean of its divisors is an integer number (56066056746).

Almost surely, 2112132113491 is an apocalyptic number.

112132113491 is a deficient number, since it is larger than the sum of its proper divisors (1).

112132113491 is an equidigital number, since it uses as much as digits as its factorization.

112132113491 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1296, while the sum is 29.

The spelling of 112132113491 in words is "one hundred twelve billion, one hundred thirty-two million, one hundred thirteen thousand, four hundred ninety-one".