Base | Representation |
---|---|
bin | 10100111000101110… |
… | …00110000000111001 |
3 | 1001221110200022121121 |
4 | 22130113012000321 |
5 | 140431041443413 |
6 | 5052402305241 |
7 | 544605626665 |
oct | 123427060071 |
9 | 31843608547 |
10 | 11213234233 |
11 | 483463a933 |
12 | 220b358221 |
13 | 1099166656 |
14 | 7853398a5 |
15 | 45965eb8d |
hex | 29c5c6039 |
11213234233 has 2 divisors, whose sum is σ = 11213234234. Its totient is φ = 11213234232.
The previous prime is 11213234231. The next prime is 11213234309. The reversal of 11213234233 is 33243231211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6703843129 + 4509391104 = 81877^2 + 67152^2 .
It is a cyclic number.
It is not a de Polignac number, because 11213234233 - 21 = 11213234231 is a prime.
Together with 11213234231, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 11213234198 and 11213234207.
It is not a weakly prime, because it can be changed into another prime (11213234231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606617116 + 5606617117.
It is an arithmetic number, because the mean of its divisors is an integer number (5606617117).
Almost surely, 211213234233 is an apocalyptic number.
It is an amenable number.
11213234233 is a deficient number, since it is larger than the sum of its proper divisors (1).
11213234233 is an equidigital number, since it uses as much as digits as its factorization.
11213234233 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2592, while the sum is 25.
Adding to 11213234233 its reverse (33243231211), we get a palindrome (44456465444).
The spelling of 11213234233 in words is "eleven billion, two hundred thirteen million, two hundred thirty-four thousand, two hundred thirty-three".
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