112151341005533 has 2 divisors, whose sum is σ = 112151341005534. Its totient is φ = 112151341005532.

The previous prime is 112151341005511. The next prime is 112151341005617. The reversal of 112151341005533 is 335500143151211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94298121761284 + 17853219244249 = 9710722^2 + 4225307^2 .

It is a cyclic number.

It is not a de Polignac number, because 112151341005533 - 2⁴² = 107753294494429 is a prime.

It is a super-2 number, since 2×112151341005533² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 112151341005493 and 112151341005502.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112151341008533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56075670502766 + 56075670502767.

It is an arithmetic number, because the mean of its divisors is an integer number (56075670502767).

Almost surely, 2^{112151341005533} is an apocalyptic number.

It is an amenable number.

112151341005533 is a deficient number, since it is larger than the sum of its proper divisors (1).

112151341005533 is an equidigital number, since it uses as much as digits as its factorization.

112151341005533 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27000, while the sum is 35.

Adding to 112151341005533 its reverse (335500143151211), we get a palindrome (447651484156744).

The spelling of 112151341005533 in words is "one hundred twelve trillion, one hundred fifty-one billion, three hundred forty-one million, five thousand, five hundred thirty-three".