Base | Representation |
---|---|
bin | 11001100000000001000100… |
… | …110101110111101100110001 |
3 | 112201002120012210012021211102 |
4 | 121200001010311313230301 |
5 | 104144441421244134432 |
6 | 1034305340443454145 |
7 | 32423444531403344 |
oct | 3140010465675461 |
9 | 481076183167742 |
10 | 112151341005617 |
11 | 3280a131244531 |
12 | 106b3821227355 |
13 | 4a76a97b79414 |
14 | 1d9a2222d845b |
15 | ce74a8dae962 |
hex | 660044d77b31 |
112151341005617 has 2 divisors, whose sum is σ = 112151341005618. Its totient is φ = 112151341005616.
The previous prime is 112151341005533. The next prime is 112151341005719. The reversal of 112151341005617 is 716500143151211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 68472050246656 + 43679290758961 = 8274784^2 + 6609031^2 .
It is a cyclic number.
It is not a de Polignac number, because 112151341005617 - 216 = 112151340940081 is a prime.
It is not a weakly prime, because it can be changed into another prime (112151341505617) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56075670502808 + 56075670502809.
It is an arithmetic number, because the mean of its divisors is an integer number (56075670502809).
Almost surely, 2112151341005617 is an apocalyptic number.
It is an amenable number.
112151341005617 is a deficient number, since it is larger than the sum of its proper divisors (1).
112151341005617 is an equidigital number, since it uses as much as digits as its factorization.
112151341005617 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25200, while the sum is 38.
Adding to 112151341005617 its reverse (716500143151211), we get a palindrome (828651484156828).
The spelling of 112151341005617 in words is "one hundred twelve trillion, one hundred fifty-one billion, three hundred forty-one million, five thousand, six hundred seventeen".
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