Base | Representation |
---|---|
bin | 1010001100110011101100… |
… | …1110011010000110110111 |
3 | 1110201011021022102211202102 |
4 | 2203030323032122012313 |
5 | 2432222113212230201 |
6 | 35504100440132315 |
7 | 2235160644443126 |
oct | 243147316320667 |
9 | 43634238384672 |
10 | 11215153242551 |
11 | 3634357699565 |
12 | 13116a416709b |
13 | 634779c5502b |
14 | 2aab5dd6babd |
15 | 146aea11326b |
hex | a333b39a1b7 |
11215153242551 has 2 divisors, whose sum is σ = 11215153242552. Its totient is φ = 11215153242550.
The previous prime is 11215153242547. The next prime is 11215153242569. The reversal of 11215153242551 is 15524235151211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11215153242551 - 22 = 11215153242547 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11215153242571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5607576621275 + 5607576621276.
It is an arithmetic number, because the mean of its divisors is an integer number (5607576621276).
Almost surely, 211215153242551 is an apocalyptic number.
11215153242551 is a deficient number, since it is larger than the sum of its proper divisors (1).
11215153242551 is an equidigital number, since it uses as much as digits as its factorization.
11215153242551 is an evil number, because the sum of its binary digits is even.
The product of its digits is 60000, while the sum is 38.
Adding to 11215153242551 its reverse (15524235151211), we get a palindrome (26739388393762).
The spelling of 11215153242551 in words is "eleven trillion, two hundred fifteen billion, one hundred fifty-three million, two hundred forty-two thousand, five hundred fifty-one".
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