Base | Representation |
---|---|
bin | 1010001100110100100111… |
… | …1111101110001110010111 |
3 | 1110201011220120201211002021 |
4 | 2203031021333232032113 |
5 | 2432223120132113111 |
6 | 35504141211354011 |
7 | 2235200043666622 |
oct | 243151177561627 |
9 | 43634816654067 |
10 | 11215401051031 |
11 | 3634474565761 |
12 | 1311753152907 |
13 | 6347b93ab078 |
14 | 2aab84c36db9 |
15 | 146b11c62d71 |
hex | a3349fee397 |
11215401051031 has 2 divisors, whose sum is σ = 11215401051032. Its totient is φ = 11215401051030.
The previous prime is 11215401051007. The next prime is 11215401051053. The reversal of 11215401051031 is 13015010451211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11215401051031 - 29 = 11215401050519 is a prime.
It is a super-2 number, since 2×112154010510312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11215401050987 and 11215401051005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11215401051331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5607700525515 + 5607700525516.
It is an arithmetic number, because the mean of its divisors is an integer number (5607700525516).
Almost surely, 211215401051031 is an apocalyptic number.
11215401051031 is a deficient number, since it is larger than the sum of its proper divisors (1).
11215401051031 is an equidigital number, since it uses as much as digits as its factorization.
11215401051031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 600, while the sum is 25.
The spelling of 11215401051031 in words is "eleven trillion, two hundred fifteen billion, four hundred one million, fifty-one thousand, thirty-one".
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