Base | Representation |
---|---|
bin | 10000010100111101000… |
… | …100010010110100101111 |
3 | 10222021002212122102112002 |
4 | 100110331010102310233 |
5 | 121340334304000421 |
6 | 2215240021402515 |
7 | 144030323066351 |
oct | 20247504226457 |
9 | 3867085572462 |
10 | 1122011000111 |
11 | 3a2929a60181 |
12 | 16155326943b |
13 | 81a60cac0b1 |
14 | 3c43c8ad0d1 |
15 | 1e2bd053b0b |
hex | 1053d112d2f |
1122011000111 has 2 divisors, whose sum is σ = 1122011000112. Its totient is φ = 1122011000110.
The previous prime is 1122011000101. The next prime is 1122011000113. The reversal of 1122011000111 is 1110001102211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1122011000111 - 222 = 1122006805807 is a prime.
Together with 1122011000113, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 1122011000092 and 1122011000101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1122011000113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561005500055 + 561005500056.
It is an arithmetic number, because the mean of its divisors is an integer number (561005500056).
Almost surely, 21122011000111 is an apocalyptic number.
1122011000111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1122011000111 is an equidigital number, since it uses as much as digits as its factorization.
1122011000111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4, while the sum is 11.
Adding to 1122011000111 its reverse (1110001102211), we get a palindrome (2232012102322).
The spelling of 1122011000111 in words is "one trillion, one hundred twenty-two billion, eleven million, one hundred eleven", and thus it is an aban number.
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