Base | Representation |
---|---|
bin | 10100111001100010… |
… | …10111000111001101 |
3 | 1001221221122011010111 |
4 | 22130301113013031 |
5 | 140434322320023 |
6 | 5053210040021 |
7 | 545021306104 |
oct | 123461270715 |
9 | 31857564114 |
10 | 11220120013 |
11 | 4838513263 |
12 | 2211719011 |
13 | 109a70788b |
14 | 78620d03b |
15 | 45a07000d |
hex | 29cc571cd |
11220120013 has 2 divisors, whose sum is σ = 11220120014. Its totient is φ = 11220120012.
The previous prime is 11220119993. The next prime is 11220120017. The reversal of 11220120013 is 31002102211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7073146404 + 4146973609 = 84102^2 + 64397^2 .
It is a cyclic number.
It is not a de Polignac number, because 11220120013 - 221 = 11218022861 is a prime.
It is a super-2 number, since 2×112201200132 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11220119975 and 11220120002.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11220120017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5610060006 + 5610060007.
It is an arithmetic number, because the mean of its divisors is an integer number (5610060007).
Almost surely, 211220120013 is an apocalyptic number.
It is an amenable number.
11220120013 is a deficient number, since it is larger than the sum of its proper divisors (1).
11220120013 is an equidigital number, since it uses as much as digits as its factorization.
11220120013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 11220120013 its reverse (31002102211), we get a palindrome (42222222224).
The spelling of 11220120013 in words is "eleven billion, two hundred twenty million, one hundred twenty thousand, thirteen".
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