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1122012220013 is a prime number
BaseRepresentation
bin10000010100111101001…
…000111100101001101101
310222021002221221101220122
4100110331020330221231
5121340340112020023
62215240103454325
7144030336340046
oct20247510745155
93867087841818
101122012220013
113a292a713763
121615537573a5
1381a61318429
143c43cb098cd
151e2bd1e52c8
hex1053d23ca6d

1122012220013 has 2 divisors, whose sum is σ = 1122012220014. Its totient is φ = 1122012220012.

The previous prime is 1122012219997. The next prime is 1122012220027. The reversal of 1122012220013 is 3100222102211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1100625497449 + 21386722564 = 1049107^2 + 146242^2 .

It is a cyclic number.

It is not a de Polignac number, because 1122012220013 - 24 = 1122012219997 is a prime.

It is a super-2 number, since 2×11220122200132 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1122012219973 and 1122012220000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1122012220513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561006110006 + 561006110007.

It is an arithmetic number, because the mean of its divisors is an integer number (561006110007).

Almost surely, 21122012220013 is an apocalyptic number.

It is an amenable number.

1122012220013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1122012220013 is an equidigital number, since it uses as much as digits as its factorization.

1122012220013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 1122012220013 its reverse (3100222102211), we get a palindrome (4222234322224).

The spelling of 1122012220013 in words is "one trillion, one hundred twenty-two billion, twelve million, two hundred twenty thousand, thirteen".