Base | Representation |
---|---|
bin | 1010001101000110010000… |
… | …0011111100000001001111 |
3 | 1110201122010101100112211121 |
4 | 2203101210003330001033 |
5 | 2432312313113043043 |
6 | 35510242540501411 |
7 | 2235425235500401 |
oct | 243214403740117 |
9 | 43648111315747 |
10 | 11220133331023 |
11 | 3636482836761 |
12 | 1312653b4a867 |
13 | 635091931846 |
14 | 2ab0b3528b71 |
15 | 146cdc434ded |
hex | a34640fc04f |
11220133331023 has 2 divisors, whose sum is σ = 11220133331024. Its totient is φ = 11220133331022.
The previous prime is 11220133331003. The next prime is 11220133331027. The reversal of 11220133331023 is 32013333102211.
It is a strong prime.
It is an emirp because it is prime and its reverse (32013333102211) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11220133331023 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11220133331027) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5610066665511 + 5610066665512.
It is an arithmetic number, because the mean of its divisors is an integer number (5610066665512).
Almost surely, 211220133331023 is an apocalyptic number.
11220133331023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11220133331023 is an equidigital number, since it uses as much as digits as its factorization.
11220133331023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 11220133331023 its reverse (32013333102211), we get a palindrome (43233466433234).
The spelling of 11220133331023 in words is "eleven trillion, two hundred twenty billion, one hundred thirty-three million, three hundred thirty-one thousand, twenty-three".
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